## Python进制转换（二进制、十进制和十六进制）

2017年10月15日 发表评论 阅读评论

```>>> hex(10)
'0xa'
>>> oct(8)
'010'
>>> oct(10)
'012'
>>> bin(10)
'0b1010'
>>> int('0xa',16)
10
>>> int('010',8)
8
>>> int('0b1010',2)
10
>>> int('0xA',16)
10```

```#!/usr/bin/env python
# coding=utf8
# ===============================================================================
#   Description   ：bin oct dec hex convert （进制转换）
# ===============================================================================
import os,sys
# global definition
# base = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F]
base = [str(x) for x in range(10)] + [ chr(x) for x in range(ord('A'),ord('A')+6)]
# bin2dec
# 二进制 to 十进制: int(str,n=10)
def bin2dec(string_num):
return str(int(string_num, 2))
# hex2dec
# 十六进制 to 十进制
def hex2dec(string_num):
return str(int(string_num.upper(), 16))
# dec2bin
# 十进制 to 二进制: bin()
def dec2bin(string_num):
num = int(string_num)
mid = []
while True:
if num == 0: break
num,rem = divmod(num, 2)
mid.append(base[rem])
return ''.join([str(x) for x in mid[::-1]])
# dec2hex
# 十进制 to 八进制: oct()
# 十进制 to 十六进制: hex()
def dec2hex(string_num):
num = int(string_num)
mid = []
while True:
if num == 0: break
num,rem = divmod(num, 16)
mid.append(base[rem])
return ''.join([str(x) for x in mid[::-1]])
# hex2tobin
# 十六进制 to 二进制: bin(int(str,16))
def hex2bin(string_num):
return dec2bin(hex2dec(string_num.upper()))
# bin2hex
# 二进制 to 十六进制: hex(int(str,2))
def bin2hex(string_num):
return dec2hex(bin2dec(string_num))```

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